WebJan 19, 2024 · When you want to redirect to a GET after a POST, the best practice is to redirect with a 303 status code, so just update your code to:. return … WebAug 20, 2024 · from fastapi import FastAPI my_app = FastAPI() @my_app.post("/getInformation") def getInformation(): return { "status" : "SUCCESS", "data" : [] } To pass request data object, you need to create a class of the data object that you intend to pass as POST body request.
How to complete FastAPI Google OAuth flow - Stack Overflow
WebMar 31, 2024 · This article takes a look at these 5 lessons learned from analyzing their docs. Optimize for time to Hello World. Start with the how and end with the why. Make all code … WebSep 15, 2024 · from fastapi import APIRouter router = APIRouter () @router.get("", response_model=Foo, include_in_schema=False) @router.get("/", response_model=Foo, include_in_schema=False) def endpoint ( bar: Bar = Depends ()): ... Edit: the implementation above has a bug, read on below for working implementations. 4 hjoukl commented on … ebonscale reach level new world
How to Create A POST Request in FastAPI - Medium
WebAug 20, 2024 · To pass request data object, you need to create a class of the data object that you intend to pass as POST body request. from pydantic import BaseModel my_app … WebFeb 10, 2024 · This is not FastAPI that triggers a POST request, it's the browser that automatically follows the redirection with the same method. By default, RedirectResponse answers with a 307 status code. In your case, you want to implement the Post/Redirect/Get pattern which expects a 303 status code ; so that the browser knows to do a GET … Webfrom fastapi import FastAPI from fastapi.openapi.docs import ( get_redoc_html, get_swagger_ui_html, get_swagger_ui_oauth2_redirect_html, ) from fastapi.staticfiles import … competition brochure