WebQuestion Calculate Δ H ° 298 for the process Sb ( s) + (5)/ (2)Cl 2 ( g) SbCl 5 ( g) from the following information: Sb ( s) + (3)/ (2)Cl 2 ( g ) SbCl 3 ( g ) Δ H ° 298 = −314 kJ SbCl 3 ( s) + Cl 2 ( g ) SbCl 5 ( g ) Δ H ° 298 = −80 kJ Expert Solution Want to see the full answer? Check out a sample Q&A here See Solution star_border WebApr 9, 2024 · Save. I am planing a trip to Australia and currently have an overnight in Sydney on the way home. We will arrive from OOL in the evening and our flight home will not leave …
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WebUse the standard free energy of formation data in Appendix G to determine the free energy change for each of the following reactions, which are run under standard state conditions and 25 °C. Identify each as either spontaneous or nonspontaneous at these conditions. (a) MnO2 (𝑠) Mn (𝑠)+O2 (𝑔) (b) H2 (𝑔)+Br2 (𝑙) 2HBr (𝑔) (c) Cu (𝑠)+S (𝑔) CuS (𝑠) Web东风高中天门中学仙桃中学2024届高三12月考试高三化学试题可能用到的相对原子质量:H1 C12 O16 Na23 Mg24 Al27 S32 Cl35.5 Cu64第I卷选择题共45分一选择题本题共15小题,每小题3分,共45分,每小题只,文库网_wenkunet.com tregarton park campsite cornwall
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WebChemistry. Chemistry questions and answers. Calculate ΔH298 ° for the process Sb (s) + 5/2Cl2 (g) SbCl5 (g) from the following information: Sb (s) + 3 2 Cl2 (g) SbCl3 (g) ΔH298 ° = −314 kJ SbCl3 (s) + Cl2 (g) SbCl5 (g) ΔH298 ° = −80 kJ. WebMar 19, 2024 · At moderately high temperatures, SbCl5 decomposes into SbCl3 and Cl2 as follows: SbCl5 (g) <---> SbCl3 (g) + Cl2 (g) ? A 65.4 g sample of SbCl5 is placed in an evacuated 5.00 L vessel and it is raised to 195oC and the system comes to equilibrium. If at this temperature 35.8% of the SbCl5 is decomposed, what is the value of Kp? Chemistry 1 … WebN2O4(g) ⇌ 2NO2(g) Δn(g) ≠ 0 Δn(g) = 0 Onde: Δn (g) = n(g) produtos - n(g) reagentes = variação do número de mols de espécies no estado gasoso. Observe que o sistema a seguir não apresenta nenhum deslocamento ou favorecimento reacional, se há aumento da pressão quando o equilíbrio dinâmico é alcançado. temperature for slow cooking beef